PLAIN AND CIVIL: EXAMPLE 4.4.1. ESTIMATION OF MARBLE TILES

Estimate the 30 x 60 marble tiles required for the 12-m long floor having a width on one end of 6.0m and 4.0m on the other. Determine the materials for class B mortar.

Using the table for marble tiles:

Size	Number	A	B	C	Sand
cm.	/sqm	bags	bags	bags	cu.m.

15 x 30	22.3	0.45	0.30	0.225	0.025
20 x 20	25.0	0.45	0.30	0.225	0.025
20 x 40	12.5	0.45	0.30	0.225	0.025
30 x 30	11.1	0.45	0.30	0.225	0.025
30 x 60	5.6	0.45	0.30	0.225	0.025
40 x 40	6.3	0.45	0.30	0.225	0.025
60 x 60	2.8	0.45	0.30	0.225	0.025

$Tiles_{marble}=5.6\frac{pcs}{m^{2}}\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \boldsymbol{336pcs\left ( 30x60 \right )}}$

$Cement_{mortar}=0.30\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \mathbf{18bags}}$

$Sand_{mortar}=0.0250\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \mathbf{1.5m^{3}}}$

Joinery:

$Polymerliquid_{joinery}=0.035\frac{gals}{m^{2}}\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \mathbf{2.10gals}}$

$Hardener_{joinery}=0.030\frac{gals}{m^{2}}\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \mathbf{1.80qts}}$

$Calsominepowder_{joinery}=0.045\frac{gals}{m^{2}}\left ( \frac{12m}{2} \right )\left ( 6.0m+4.0m \right )={\color{Red} \mathbf{2.70qts}}$

Back to 4.0. Estimating Tiles

PLAIN AND CIVIL

Pages

Wednesday 24 July 2019

EXAMPLE 4.4.1. ESTIMATION OF MARBLE TILES

1 comment: