The same procedure is to be used in solving for the angle between the other cable AC and strut AO. The working equation used is still:
However, the difference of this example from the previous one is the determination of the coordinates of the three points in consideration. Notice that point C has an angle and the direct distance of the point from point O, thus, we should break the 5-ft distance into its -x and -z components to the have coordinates.
POINTS | i, ft | j, ft | k, ft |
---|---|---|---|
A | 0 | 6 | 2 |
C | 5cos60=2.5 | 0 | 5sin60=4.33 |
O | 0 | 0 | 0 |
The properties of strut AO will remain the same from the previous example.
Solve for the parameters of vector AC.
Take the scalar of vector AC.
Take the Dot Product of the two vectors:
Substitute the known parameters to the working equation:
ANSWER
Back to 4.1. INTRODUCTION TO DOT PRODUCT
This comment has been removed by the author.
ReplyDeletethank you for posting very informative for help go to the link Structural Analysis in USA
ReplyDeleteWonderful job. What a great experience of vectorization.. I understand your point thoroughly. Thank you very much...
ReplyDeleteHanna from Vector Tracing