VERTICAL DISTRIBUTION OF BASE SHEAR: Example 1

PROBLEM: From Problem 1-1, distribute the base shear to the respective floors.

Note that the fundamental period, T, of the structure, as computed in base shear is equal to 0.7727 seconds, which is greater than 0.70s, thus, the base shear must be reduced by Ft before distributing among the floors.
                         
                                                           
                                                           

Thus, the base shear to be distributed is computed as:

                                                           
                                          

• Fill up the table using just the weight per floor and the relative height of each floor. 
• Multiply weight by relative height. Take summation of (weight x height)
• Take the percentage distribution of each (weight x height). For the following example, the summation of (weight x height) = 169040, then:   

                                   
                                         
                                   
                                   
                                   
                                   
                                   
                                    

• Compute for the force by multiplying the computed base shear to the Cvx.

                                     
                                     
                                                            
                                     
                                     
                                    
                                    
                                    

FLOORS	WEIGHT	HEIGHT	WxH	Cvx	FORCE
RD	1700	23.20	39440	0.23	235.21
7Flr	1800	20.00	36000	0.21	214.70
6Flr	1800	16.80	30240	0.18	180.35
5Flr	1800	13.60	24480	0.14	146.00
4Flr	1800	10.40	18720	0.11	111.64
3Flr	1800	7.20	12960	0.08	77.29
2Flr	1800	4.00	7200	0.04	42.94
GFlr	1500	0.00	0	0	0.00
Σ			169040	1	1008.13

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